Metamath Proof Explorer


Theorem frege48

Description: Closed form of syllogism with internal disjunction. If ph is a sufficient condition for the occurrence of ch or ps and if ch , as well as ps , is a sufficient condition for th , then ph is a sufficient condition for th . See application in frege101 . Proposition 48 of Frege1879 p. 49. (Contributed by RP, 24-Dec-2019) (Proof modification is discouraged.)

Ref Expression
Assertion frege48 ( ( 𝜑 → ( ¬ 𝜓𝜒 ) ) → ( ( 𝜒𝜃 ) → ( ( 𝜓𝜃 ) → ( 𝜑𝜃 ) ) ) )

Proof

Step Hyp Ref Expression
1 frege47 ( ( ¬ 𝜓𝜒 ) → ( ( 𝜒𝜃 ) → ( ( 𝜓𝜃 ) → 𝜃 ) ) )
2 frege23 ( ( ( ¬ 𝜓𝜒 ) → ( ( 𝜒𝜃 ) → ( ( 𝜓𝜃 ) → 𝜃 ) ) ) → ( ( 𝜑 → ( ¬ 𝜓𝜒 ) ) → ( ( 𝜒𝜃 ) → ( ( 𝜓𝜃 ) → ( 𝜑𝜃 ) ) ) ) )
3 1 2 ax-mp ( ( 𝜑 → ( ¬ 𝜓𝜒 ) ) → ( ( 𝜒𝜃 ) → ( ( 𝜓𝜃 ) → ( 𝜑𝜃 ) ) ) )