Metamath Proof Explorer


Theorem funfnd

Description: A function is a function on its domain. (Contributed by Glauco Siliprandi, 23-Oct-2021)

Ref Expression
Hypothesis funfnd.1 ( 𝜑 → Fun 𝐴 )
Assertion funfnd ( 𝜑𝐴 Fn dom 𝐴 )

Proof

Step Hyp Ref Expression
1 funfnd.1 ( 𝜑 → Fun 𝐴 )
2 funfn ( Fun 𝐴𝐴 Fn dom 𝐴 )
3 1 2 sylib ( 𝜑𝐴 Fn dom 𝐴 )