Metamath Proof Explorer


Theorem funssfv

Description: The value of a member of the domain of a subclass of a function. (Contributed by NM, 15-Aug-1994)

Ref Expression
Assertion funssfv ( ( Fun 𝐹 ∧ 𝐺 ⊆ 𝐹 ∧ 𝐴 ∈ dom 𝐺 ) → ( 𝐹 ‘ 𝐴 ) = ( 𝐺 ‘ 𝐴 ) )

Proof

Step Hyp Ref Expression
1 fvres ⊢ ( 𝐴 ∈ dom 𝐺 → ( ( 𝐹 ↾ dom 𝐺 ) ‘ 𝐴 ) = ( 𝐹 ‘ 𝐴 ) )
2 1 eqcomd ⊢ ( 𝐴 ∈ dom 𝐺 → ( 𝐹 ‘ 𝐴 ) = ( ( 𝐹 ↾ dom 𝐺 ) ‘ 𝐴 ) )
3 funssres ⊢ ( ( Fun 𝐹 ∧ 𝐺 ⊆ 𝐹 ) → ( 𝐹 ↾ dom 𝐺 ) = 𝐺 )
4 3 fveq1d ⊢ ( ( Fun 𝐹 ∧ 𝐺 ⊆ 𝐹 ) → ( ( 𝐹 ↾ dom 𝐺 ) ‘ 𝐴 ) = ( 𝐺 ‘ 𝐴 ) )
5 2 4 sylan9eqr ⊢ ( ( ( Fun 𝐹 ∧ 𝐺 ⊆ 𝐹 ) ∧ 𝐴 ∈ dom 𝐺 ) → ( 𝐹 ‘ 𝐴 ) = ( 𝐺 ‘ 𝐴 ) )
6 5 3impa ⊢ ( ( Fun 𝐹 ∧ 𝐺 ⊆ 𝐹 ∧ 𝐴 ∈ dom 𝐺 ) → ( 𝐹 ‘ 𝐴 ) = ( 𝐺 ‘ 𝐴 ) )