Metamath Proof Explorer


Theorem funssfv

Description: The value of a member of the domain of a subclass of a function. (Contributed by NM, 15-Aug-1994)

Ref Expression
Assertion funssfv ⊢ Fun ⁡ F ∧ G ⊆ F ∧ A ∈ dom ⁡ G → F ⁡ A = G ⁡ A

Proof

Step Hyp Ref Expression
1 fvres ⊢ A ∈ dom ⁡ G → F ↾ dom ⁡ G ⁡ A = F ⁡ A
2 1 eqcomd ⊢ A ∈ dom ⁡ G → F ⁡ A = F ↾ dom ⁡ G ⁡ A
3 funssres ⊢ Fun ⁡ F ∧ G ⊆ F → F ↾ dom ⁡ G = G
4 3 fveq1d ⊢ Fun ⁡ F ∧ G ⊆ F → F ↾ dom ⁡ G ⁡ A = G ⁡ A
5 2 4 sylan9eqr ⊢ Fun ⁡ F ∧ G ⊆ F ∧ A ∈ dom ⁡ G → F ⁡ A = G ⁡ A
6 5 3impa ⊢ Fun ⁡ F ∧ G ⊆ F ∧ A ∈ dom ⁡ G → F ⁡ A = G ⁡ A