Metamath Proof Explorer
Description: Value of a function composition. (Contributed by NM, 3-Jan-2004)
(Revised by Mario Carneiro, 26-Dec-2014)
|
|
Ref |
Expression |
|
Assertion |
fvco3 |
⊢ ( ( 𝐺 : 𝐴 ⟶ 𝐵 ∧ 𝐶 ∈ 𝐴 ) → ( ( 𝐹 ∘ 𝐺 ) ‘ 𝐶 ) = ( 𝐹 ‘ ( 𝐺 ‘ 𝐶 ) ) ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
ffn |
⊢ ( 𝐺 : 𝐴 ⟶ 𝐵 → 𝐺 Fn 𝐴 ) |
2 |
|
fvco2 |
⊢ ( ( 𝐺 Fn 𝐴 ∧ 𝐶 ∈ 𝐴 ) → ( ( 𝐹 ∘ 𝐺 ) ‘ 𝐶 ) = ( 𝐹 ‘ ( 𝐺 ‘ 𝐶 ) ) ) |
3 |
1 2
|
sylan |
⊢ ( ( 𝐺 : 𝐴 ⟶ 𝐵 ∧ 𝐶 ∈ 𝐴 ) → ( ( 𝐹 ∘ 𝐺 ) ‘ 𝐶 ) = ( 𝐹 ‘ ( 𝐺 ‘ 𝐶 ) ) ) |