Metamath Proof Explorer


Theorem fveq12d

Description: Equality deduction for function value. (Contributed by FL, 22-Dec-2008)

Ref Expression
Hypotheses fveq12d.1 ⊢ ( 𝜑 → 𝐹 = 𝐺 )
fveq12d.2 ⊢ ( 𝜑 → 𝐴 = 𝐵 )
Assertion fveq12d ( 𝜑 → ( 𝐹 ‘ 𝐴 ) = ( 𝐺 ‘ 𝐵 ) )

Proof

Step Hyp Ref Expression
1 fveq12d.1 ⊢ ( 𝜑 → 𝐹 = 𝐺 )
2 fveq12d.2 ⊢ ( 𝜑 → 𝐴 = 𝐵 )
3 1 fveq1d ⊢ ( 𝜑 → ( 𝐹 ‘ 𝐴 ) = ( 𝐺 ‘ 𝐴 ) )
4 2 fveq2d ⊢ ( 𝜑 → ( 𝐺 ‘ 𝐴 ) = ( 𝐺 ‘ 𝐵 ) )
5 3 4 eqtrd ⊢ ( 𝜑 → ( 𝐹 ‘ 𝐴 ) = ( 𝐺 ‘ 𝐵 ) )