Metamath Proof Explorer


Theorem gblacfnac2d

Description: If G is a global choice function, then the Axiom of Choice holds. This is gblacfnacd expressed using CHOICE . (Contributed by BTernaryTau, 25-Sep-2026)

Ref Expression
Hypotheses gblacfnac2d.1 ⊢ ( 𝜑 → 𝐺 Fn V )
gblacfnac2d.2 ⊢ ( 𝜑 → ∀ 𝑧 ( 𝑧 ≠ ∅ → ( 𝐺 ‘ 𝑧 ) ∈ 𝑧 ) )
Assertion gblacfnac2d ( 𝜑 → CHOICE )

Proof

Step Hyp Ref Expression
1 gblacfnac2d.1 ⊢ ( 𝜑 → 𝐺 Fn V )
2 gblacfnac2d.2 ⊢ ( 𝜑 → ∀ 𝑧 ( 𝑧 ≠ ∅ → ( 𝐺 ‘ 𝑧 ) ∈ 𝑧 ) )
3 1 2 gblacfnacd ⊢ ( 𝜑 → ∀ 𝑥 ∃ 𝑓 ( 𝑓 Fn 𝑥 ∧ ∀ 𝑧 ∈ 𝑥 ( 𝑧 ≠ ∅ → ( 𝑓 ‘ 𝑧 ) ∈ 𝑧 ) ) )
4 dfac4 ⊢ ( CHOICE ↔ ∀ 𝑥 ∃ 𝑓 ( 𝑓 Fn 𝑥 ∧ ∀ 𝑧 ∈ 𝑥 ( 𝑧 ≠ ∅ → ( 𝑓 ‘ 𝑧 ) ∈ 𝑧 ) ) )
5 3 4 sylibr ⊢ ( 𝜑 → CHOICE )