Metamath Proof Explorer


Theorem hashomiso

Description: The # function yields an order isomorphism between _om and NN0 . (Contributed by Eric Schmidt, 7-Jul-2026)

Ref Expression
Assertion hashomiso ( ♯ ↾ ω ) Isom E , < ( ω , ℕ0 )

Proof

Step Hyp Ref Expression
1 hashomf1o ( ♯ ↾ ω ) : ω –1-1-onto→ ℕ0
2 epel ( 𝑥 E 𝑦𝑥𝑦 )
3 hashnnltb ( ( 𝑥 ∈ ω ∧ 𝑦 ∈ ω ) → ( 𝑥𝑦 ↔ ( ♯ ‘ 𝑥 ) < ( ♯ ‘ 𝑦 ) ) )
4 2 3 bitrid ( ( 𝑥 ∈ ω ∧ 𝑦 ∈ ω ) → ( 𝑥 E 𝑦 ↔ ( ♯ ‘ 𝑥 ) < ( ♯ ‘ 𝑦 ) ) )
5 fvres ( 𝑥 ∈ ω → ( ( ♯ ↾ ω ) ‘ 𝑥 ) = ( ♯ ‘ 𝑥 ) )
6 fvres ( 𝑦 ∈ ω → ( ( ♯ ↾ ω ) ‘ 𝑦 ) = ( ♯ ‘ 𝑦 ) )
7 5 6 breqan12d ( ( 𝑥 ∈ ω ∧ 𝑦 ∈ ω ) → ( ( ( ♯ ↾ ω ) ‘ 𝑥 ) < ( ( ♯ ↾ ω ) ‘ 𝑦 ) ↔ ( ♯ ‘ 𝑥 ) < ( ♯ ‘ 𝑦 ) ) )
8 4 7 bitr4d ( ( 𝑥 ∈ ω ∧ 𝑦 ∈ ω ) → ( 𝑥 E 𝑦 ↔ ( ( ♯ ↾ ω ) ‘ 𝑥 ) < ( ( ♯ ↾ ω ) ‘ 𝑦 ) ) )
9 8 rgen2 𝑥 ∈ ω ∀ 𝑦 ∈ ω ( 𝑥 E 𝑦 ↔ ( ( ♯ ↾ ω ) ‘ 𝑥 ) < ( ( ♯ ↾ ω ) ‘ 𝑦 ) )
10 df-isom ( ( ♯ ↾ ω ) Isom E , < ( ω , ℕ0 ) ↔ ( ( ♯ ↾ ω ) : ω –1-1-onto→ ℕ0 ∧ ∀ 𝑥 ∈ ω ∀ 𝑦 ∈ ω ( 𝑥 E 𝑦 ↔ ( ( ♯ ↾ ω ) ‘ 𝑥 ) < ( ( ♯ ↾ ω ) ‘ 𝑦 ) ) ) )
11 1 9 10 mpbir2an ( ♯ ↾ ω ) Isom E , < ( ω , ℕ0 )