Metamath Proof Explorer


Theorem homacd

Description: The codomain of an arrow with known domain and codomain. (Contributed by Mario Carneiro, 11-Jan-2017)

Ref Expression
Hypothesis homahom.h 𝐻 = ( Homa𝐶 )
Assertion homacd ( 𝐹 ∈ ( 𝑋 𝐻 𝑌 ) → ( coda𝐹 ) = 𝑌 )

Proof

Step Hyp Ref Expression
1 homahom.h 𝐻 = ( Homa𝐶 )
2 df-coda coda = ( 2nd ∘ 1st )
3 2 fveq1i ( coda𝐹 ) = ( ( 2nd ∘ 1st ) ‘ 𝐹 )
4 fo1st 1st : V –onto→ V
5 fof ( 1st : V –onto→ V → 1st : V ⟶ V )
6 4 5 ax-mp 1st : V ⟶ V
7 elex ( 𝐹 ∈ ( 𝑋 𝐻 𝑌 ) → 𝐹 ∈ V )
8 fvco3 ( ( 1st : V ⟶ V ∧ 𝐹 ∈ V ) → ( ( 2nd ∘ 1st ) ‘ 𝐹 ) = ( 2nd ‘ ( 1st𝐹 ) ) )
9 6 7 8 sylancr ( 𝐹 ∈ ( 𝑋 𝐻 𝑌 ) → ( ( 2nd ∘ 1st ) ‘ 𝐹 ) = ( 2nd ‘ ( 1st𝐹 ) ) )
10 3 9 syl5eq ( 𝐹 ∈ ( 𝑋 𝐻 𝑌 ) → ( coda𝐹 ) = ( 2nd ‘ ( 1st𝐹 ) ) )
11 1 homarel Rel ( 𝑋 𝐻 𝑌 )
12 1st2ndbr ( ( Rel ( 𝑋 𝐻 𝑌 ) ∧ 𝐹 ∈ ( 𝑋 𝐻 𝑌 ) ) → ( 1st𝐹 ) ( 𝑋 𝐻 𝑌 ) ( 2nd𝐹 ) )
13 11 12 mpan ( 𝐹 ∈ ( 𝑋 𝐻 𝑌 ) → ( 1st𝐹 ) ( 𝑋 𝐻 𝑌 ) ( 2nd𝐹 ) )
14 1 homa1 ( ( 1st𝐹 ) ( 𝑋 𝐻 𝑌 ) ( 2nd𝐹 ) → ( 1st𝐹 ) = ⟨ 𝑋 , 𝑌 ⟩ )
15 13 14 syl ( 𝐹 ∈ ( 𝑋 𝐻 𝑌 ) → ( 1st𝐹 ) = ⟨ 𝑋 , 𝑌 ⟩ )
16 15 fveq2d ( 𝐹 ∈ ( 𝑋 𝐻 𝑌 ) → ( 2nd ‘ ( 1st𝐹 ) ) = ( 2nd ‘ ⟨ 𝑋 , 𝑌 ⟩ ) )
17 eqid ( Base ‘ 𝐶 ) = ( Base ‘ 𝐶 )
18 1 17 homarcl2 ( 𝐹 ∈ ( 𝑋 𝐻 𝑌 ) → ( 𝑋 ∈ ( Base ‘ 𝐶 ) ∧ 𝑌 ∈ ( Base ‘ 𝐶 ) ) )
19 op2ndg ( ( 𝑋 ∈ ( Base ‘ 𝐶 ) ∧ 𝑌 ∈ ( Base ‘ 𝐶 ) ) → ( 2nd ‘ ⟨ 𝑋 , 𝑌 ⟩ ) = 𝑌 )
20 18 19 syl ( 𝐹 ∈ ( 𝑋 𝐻 𝑌 ) → ( 2nd ‘ ⟨ 𝑋 , 𝑌 ⟩ ) = 𝑌 )
21 10 16 20 3eqtrd ( 𝐹 ∈ ( 𝑋 𝐻 𝑌 ) → ( coda𝐹 ) = 𝑌 )