Metamath Proof Explorer


Theorem hvsub0

Description: Subtraction of a zero vector. (Contributed by NM, 2-Apr-2000) (New usage is discouraged.)

Ref Expression
Assertion hvsub0 ( 𝐴 ∈ ℋ → ( 𝐴 −ℎ 0ℎ ) = 𝐴 )

Proof

Step Hyp Ref Expression
1 ax-hv0cl ⊢ 0ℎ ∈ ℋ
2 hvsubval ⊢ ( ( 𝐴 ∈ ℋ ∧ 0ℎ ∈ ℋ ) → ( 𝐴 −ℎ 0ℎ ) = ( 𝐴 +ℎ ( - 1 ·ℎ 0ℎ ) ) )
3 1 2 mpan2 ⊢ ( 𝐴 ∈ ℋ → ( 𝐴 −ℎ 0ℎ ) = ( 𝐴 +ℎ ( - 1 ·ℎ 0ℎ ) ) )
4 neg1cn ⊢ - 1 ∈ ℂ
5 hvmul0 ⊢ ( - 1 ∈ ℂ → ( - 1 ·ℎ 0ℎ ) = 0ℎ )
6 4 5 ax-mp ⊢ ( - 1 ·ℎ 0ℎ ) = 0ℎ
7 6 oveq2i ⊢ ( 𝐴 +ℎ ( - 1 ·ℎ 0ℎ ) ) = ( 𝐴 +ℎ 0ℎ )
8 3 7 eqtrdi ⊢ ( 𝐴 ∈ ℋ → ( 𝐴 −ℎ 0ℎ ) = ( 𝐴 +ℎ 0ℎ ) )
9 ax-hvaddid ⊢ ( 𝐴 ∈ ℋ → ( 𝐴 +ℎ 0ℎ ) = 𝐴 )
10 8 9 eqtrd ⊢ ( 𝐴 ∈ ℋ → ( 𝐴 −ℎ 0ℎ ) = 𝐴 )