Metamath Proof Explorer


Theorem ifpxorxorb

Description: Factor conditional logic operator over xor in terms 2 and 3. (Contributed by RP, 21-Apr-2020)

Ref Expression
Assertion ifpxorxorb ( if- ( 𝜑 , ( 𝜓 ⊻ 𝜒 ) , ( 𝜃 ⊻ 𝜏 ) ) ↔ ( if- ( 𝜑 , 𝜓 , 𝜃 ) ⊻ if- ( 𝜑 , 𝜒 , 𝜏 ) ) )

Proof

Step Hyp Ref Expression
1 df-xor ⊢ ( ( 𝜓 ⊻ 𝜒 ) ↔ ¬ ( 𝜓 ↔ 𝜒 ) )
2 df-xor ⊢ ( ( 𝜃 ⊻ 𝜏 ) ↔ ¬ ( 𝜃 ↔ 𝜏 ) )
3 ifpbi23 ⊢ ( ( ( ( 𝜓 ⊻ 𝜒 ) ↔ ¬ ( 𝜓 ↔ 𝜒 ) ) ∧ ( ( 𝜃 ⊻ 𝜏 ) ↔ ¬ ( 𝜃 ↔ 𝜏 ) ) ) → ( if- ( 𝜑 , ( 𝜓 ⊻ 𝜒 ) , ( 𝜃 ⊻ 𝜏 ) ) ↔ if- ( 𝜑 , ¬ ( 𝜓 ↔ 𝜒 ) , ¬ ( 𝜃 ↔ 𝜏 ) ) ) )
4 1 2 3 mp2an ⊢ ( if- ( 𝜑 , ( 𝜓 ⊻ 𝜒 ) , ( 𝜃 ⊻ 𝜏 ) ) ↔ if- ( 𝜑 , ¬ ( 𝜓 ↔ 𝜒 ) , ¬ ( 𝜃 ↔ 𝜏 ) ) )
5 ifpbibib ⊢ ( if- ( 𝜑 , ( 𝜓 ↔ 𝜒 ) , ( 𝜃 ↔ 𝜏 ) ) ↔ ( if- ( 𝜑 , 𝜓 , 𝜃 ) ↔ if- ( 𝜑 , 𝜒 , 𝜏 ) ) )
6 5 notbii ⊢ ( ¬ if- ( 𝜑 , ( 𝜓 ↔ 𝜒 ) , ( 𝜃 ↔ 𝜏 ) ) ↔ ¬ ( if- ( 𝜑 , 𝜓 , 𝜃 ) ↔ if- ( 𝜑 , 𝜒 , 𝜏 ) ) )
7 ifpnotnotb ⊢ ( if- ( 𝜑 , ¬ ( 𝜓 ↔ 𝜒 ) , ¬ ( 𝜃 ↔ 𝜏 ) ) ↔ ¬ if- ( 𝜑 , ( 𝜓 ↔ 𝜒 ) , ( 𝜃 ↔ 𝜏 ) ) )
8 df-xor ⊢ ( ( if- ( 𝜑 , 𝜓 , 𝜃 ) ⊻ if- ( 𝜑 , 𝜒 , 𝜏 ) ) ↔ ¬ ( if- ( 𝜑 , 𝜓 , 𝜃 ) ↔ if- ( 𝜑 , 𝜒 , 𝜏 ) ) )
9 6 7 8 3bitr4i ⊢ ( if- ( 𝜑 , ¬ ( 𝜓 ↔ 𝜒 ) , ¬ ( 𝜃 ↔ 𝜏 ) ) ↔ ( if- ( 𝜑 , 𝜓 , 𝜃 ) ⊻ if- ( 𝜑 , 𝜒 , 𝜏 ) ) )
10 4 9 bitri ⊢ ( if- ( 𝜑 , ( 𝜓 ⊻ 𝜒 ) , ( 𝜃 ⊻ 𝜏 ) ) ↔ ( if- ( 𝜑 , 𝜓 , 𝜃 ) ⊻ if- ( 𝜑 , 𝜒 , 𝜏 ) ) )