Metamath Proof Explorer


Theorem iineq2d

Description: Equality deduction for indexed intersection. (Contributed by NM, 7-Dec-2011)

Ref Expression
Hypotheses iineq2d.1 𝑥 𝜑
iineq2d.2 ( ( 𝜑𝑥𝐴 ) → 𝐵 = 𝐶 )
Assertion iineq2d ( 𝜑 𝑥𝐴 𝐵 = 𝑥𝐴 𝐶 )

Proof

Step Hyp Ref Expression
1 iineq2d.1 𝑥 𝜑
2 iineq2d.2 ( ( 𝜑𝑥𝐴 ) → 𝐵 = 𝐶 )
3 2 ex ( 𝜑 → ( 𝑥𝐴𝐵 = 𝐶 ) )
4 1 3 ralrimi ( 𝜑 → ∀ 𝑥𝐴 𝐵 = 𝐶 )
5 iineq2 ( ∀ 𝑥𝐴 𝐵 = 𝐶 𝑥𝐴 𝐵 = 𝑥𝐴 𝐶 )
6 4 5 syl ( 𝜑 𝑥𝐴 𝐵 = 𝑥𝐴 𝐶 )