Metamath Proof Explorer


Theorem indsumhash

Description: The finite sum of the indicator function is the number of elements of the corresponding subset. (Contributed by AV, 10-Apr-2026)

Ref Expression
Hypothesis indsumhash.f 1 = ( ( 𝟭 ‘ 𝑂 ) ‘ 𝐴 )
Assertion indsumhash ( ( 𝑂 ∈ Fin ∧ 𝐴𝑂 ) → Σ 𝑘𝑂 ( 1𝑘 ) = ( ♯ ‘ 𝐴 ) )

Proof

Step Hyp Ref Expression
1 indsumhash.f 1 = ( ( 𝟭 ‘ 𝑂 ) ‘ 𝐴 )
2 1 fveq1i ( 1𝑘 ) = ( ( ( 𝟭 ‘ 𝑂 ) ‘ 𝐴 ) ‘ 𝑘 )
3 fvindre ( ( ( 𝑂 ∈ Fin ∧ 𝐴𝑂 ) ∧ 𝑘𝑂 ) → ( ( ( 𝟭 ‘ 𝑂 ) ‘ 𝐴 ) ‘ 𝑘 ) ∈ ℝ )
4 3 recnd ( ( ( 𝑂 ∈ Fin ∧ 𝐴𝑂 ) ∧ 𝑘𝑂 ) → ( ( ( 𝟭 ‘ 𝑂 ) ‘ 𝐴 ) ‘ 𝑘 ) ∈ ℂ )
5 4 mulridd ( ( ( 𝑂 ∈ Fin ∧ 𝐴𝑂 ) ∧ 𝑘𝑂 ) → ( ( ( ( 𝟭 ‘ 𝑂 ) ‘ 𝐴 ) ‘ 𝑘 ) · 1 ) = ( ( ( 𝟭 ‘ 𝑂 ) ‘ 𝐴 ) ‘ 𝑘 ) )
6 2 5 eqtr4id ( ( ( 𝑂 ∈ Fin ∧ 𝐴𝑂 ) ∧ 𝑘𝑂 ) → ( 1𝑘 ) = ( ( ( ( 𝟭 ‘ 𝑂 ) ‘ 𝐴 ) ‘ 𝑘 ) · 1 ) )
7 6 ralrimiva ( ( 𝑂 ∈ Fin ∧ 𝐴𝑂 ) → ∀ 𝑘𝑂 ( 1𝑘 ) = ( ( ( ( 𝟭 ‘ 𝑂 ) ‘ 𝐴 ) ‘ 𝑘 ) · 1 ) )
8 7 sumeq2d ( ( 𝑂 ∈ Fin ∧ 𝐴𝑂 ) → Σ 𝑘𝑂 ( 1𝑘 ) = Σ 𝑘𝑂 ( ( ( ( 𝟭 ‘ 𝑂 ) ‘ 𝐴 ) ‘ 𝑘 ) · 1 ) )
9 simpl ( ( 𝑂 ∈ Fin ∧ 𝐴𝑂 ) → 𝑂 ∈ Fin )
10 simpr ( ( 𝑂 ∈ Fin ∧ 𝐴𝑂 ) → 𝐴𝑂 )
11 1cnd ( ( ( 𝑂 ∈ Fin ∧ 𝐴𝑂 ) ∧ 𝑘𝑂 ) → 1 ∈ ℂ )
12 9 10 11 indsum ( ( 𝑂 ∈ Fin ∧ 𝐴𝑂 ) → Σ 𝑘𝑂 ( ( ( ( 𝟭 ‘ 𝑂 ) ‘ 𝐴 ) ‘ 𝑘 ) · 1 ) = Σ 𝑘𝐴 1 )
13 ssfi ( ( 𝑂 ∈ Fin ∧ 𝐴𝑂 ) → 𝐴 ∈ Fin )
14 fsumconst1 ( 𝐴 ∈ Fin → Σ 𝑘𝐴 1 = ( ♯ ‘ 𝐴 ) )
15 13 14 syl ( ( 𝑂 ∈ Fin ∧ 𝐴𝑂 ) → Σ 𝑘𝐴 1 = ( ♯ ‘ 𝐴 ) )
16 8 12 15 3eqtrd ( ( 𝑂 ∈ Fin ∧ 𝐴𝑂 ) → Σ 𝑘𝑂 ( 1𝑘 ) = ( ♯ ‘ 𝐴 ) )