Metamath Proof Explorer


Theorem iscld3

Description: A subset is closed iff it equals its own closure. (Contributed by NM, 2-Oct-2006)

Ref Expression
Hypothesis clscld.1 ⊢ 𝑋 = ∪ 𝐽
Assertion iscld3 ( ( 𝐽 ∈ Top ∧ 𝑆 ⊆ 𝑋 ) → ( 𝑆 ∈ ( Clsd ‘ 𝐽 ) ↔ ( ( cls ‘ 𝐽 ) ‘ 𝑆 ) = 𝑆 ) )

Proof

Step Hyp Ref Expression
1 clscld.1 ⊢ 𝑋 = ∪ 𝐽
2 cldcls ⊢ ( 𝑆 ∈ ( Clsd ‘ 𝐽 ) → ( ( cls ‘ 𝐽 ) ‘ 𝑆 ) = 𝑆 )
3 1 clscld ⊢ ( ( 𝐽 ∈ Top ∧ 𝑆 ⊆ 𝑋 ) → ( ( cls ‘ 𝐽 ) ‘ 𝑆 ) ∈ ( Clsd ‘ 𝐽 ) )
4 eleq1 ⊢ ( ( ( cls ‘ 𝐽 ) ‘ 𝑆 ) = 𝑆 → ( ( ( cls ‘ 𝐽 ) ‘ 𝑆 ) ∈ ( Clsd ‘ 𝐽 ) ↔ 𝑆 ∈ ( Clsd ‘ 𝐽 ) ) )
5 3 4 syl5ibcom ⊢ ( ( 𝐽 ∈ Top ∧ 𝑆 ⊆ 𝑋 ) → ( ( ( cls ‘ 𝐽 ) ‘ 𝑆 ) = 𝑆 → 𝑆 ∈ ( Clsd ‘ 𝐽 ) ) )
6 2 5 impbid2 ⊢ ( ( 𝐽 ∈ Top ∧ 𝑆 ⊆ 𝑋 ) → ( 𝑆 ∈ ( Clsd ‘ 𝐽 ) ↔ ( ( cls ‘ 𝐽 ) ‘ 𝑆 ) = 𝑆 ) )