Metamath Proof Explorer


Theorem isofr2

Description: A weak form of isofr that does not need Replacement. (Contributed by Mario Carneiro, 18-Nov-2014)

Ref Expression
Assertion isofr2 ( ( 𝐻 Isom 𝑅 , 𝑆 ( 𝐴 , 𝐵 ) ∧ 𝐵 ∈ 𝑉 ) → ( 𝑆 Fr 𝐵 → 𝑅 Fr 𝐴 ) )

Proof

Step Hyp Ref Expression
1 simpl ⊢ ( ( 𝐻 Isom 𝑅 , 𝑆 ( 𝐴 , 𝐵 ) ∧ 𝐵 ∈ 𝑉 ) → 𝐻 Isom 𝑅 , 𝑆 ( 𝐴 , 𝐵 ) )
2 imassrn ⊢ ( 𝐻 “ 𝑥 ) ⊆ ran 𝐻
3 isof1o ⊢ ( 𝐻 Isom 𝑅 , 𝑆 ( 𝐴 , 𝐵 ) → 𝐻 : 𝐴 –1-1-onto→ 𝐵 )
4 f1of ⊢ ( 𝐻 : 𝐴 –1-1-onto→ 𝐵 → 𝐻 : 𝐴 ⟶ 𝐵 )
5 frn ⊢ ( 𝐻 : 𝐴 ⟶ 𝐵 → ran 𝐻 ⊆ 𝐵 )
6 3 4 5 3syl ⊢ ( 𝐻 Isom 𝑅 , 𝑆 ( 𝐴 , 𝐵 ) → ran 𝐻 ⊆ 𝐵 )
7 2 6 sstrid ⊢ ( 𝐻 Isom 𝑅 , 𝑆 ( 𝐴 , 𝐵 ) → ( 𝐻 “ 𝑥 ) ⊆ 𝐵 )
8 ssexg ⊢ ( ( ( 𝐻 “ 𝑥 ) ⊆ 𝐵 ∧ 𝐵 ∈ 𝑉 ) → ( 𝐻 “ 𝑥 ) ∈ V )
9 7 8 sylan ⊢ ( ( 𝐻 Isom 𝑅 , 𝑆 ( 𝐴 , 𝐵 ) ∧ 𝐵 ∈ 𝑉 ) → ( 𝐻 “ 𝑥 ) ∈ V )
10 1 9 isofrlem ⊢ ( ( 𝐻 Isom 𝑅 , 𝑆 ( 𝐴 , 𝐵 ) ∧ 𝐵 ∈ 𝑉 ) → ( 𝑆 Fr 𝐵 → 𝑅 Fr 𝐴 ) )