Metamath Proof Explorer


Theorem isrnghm2d

Description: Demonstration of non-unital ring homomorphism. (Contributed by AV, 23-Feb-2020)

Ref Expression
Hypotheses isrnghmd.b 𝐵 = ( Base ‘ 𝑅 )
isrnghmd.t · = ( .r𝑅 )
isrnghmd.u × = ( .r𝑆 )
isrnghmd.r ( 𝜑𝑅 ∈ Rng )
isrnghmd.s ( 𝜑𝑆 ∈ Rng )
isrnghmd.ht ( ( 𝜑 ∧ ( 𝑥𝐵𝑦𝐵 ) ) → ( 𝐹 ‘ ( 𝑥 · 𝑦 ) ) = ( ( 𝐹𝑥 ) × ( 𝐹𝑦 ) ) )
isrnghm2d.f ( 𝜑𝐹 ∈ ( 𝑅 GrpHom 𝑆 ) )
Assertion isrnghm2d ( 𝜑𝐹 ∈ ( 𝑅 RngHomo 𝑆 ) )

Proof

Step Hyp Ref Expression
1 isrnghmd.b 𝐵 = ( Base ‘ 𝑅 )
2 isrnghmd.t · = ( .r𝑅 )
3 isrnghmd.u × = ( .r𝑆 )
4 isrnghmd.r ( 𝜑𝑅 ∈ Rng )
5 isrnghmd.s ( 𝜑𝑆 ∈ Rng )
6 isrnghmd.ht ( ( 𝜑 ∧ ( 𝑥𝐵𝑦𝐵 ) ) → ( 𝐹 ‘ ( 𝑥 · 𝑦 ) ) = ( ( 𝐹𝑥 ) × ( 𝐹𝑦 ) ) )
7 isrnghm2d.f ( 𝜑𝐹 ∈ ( 𝑅 GrpHom 𝑆 ) )
8 4 5 jca ( 𝜑 → ( 𝑅 ∈ Rng ∧ 𝑆 ∈ Rng ) )
9 6 ralrimivva ( 𝜑 → ∀ 𝑥𝐵𝑦𝐵 ( 𝐹 ‘ ( 𝑥 · 𝑦 ) ) = ( ( 𝐹𝑥 ) × ( 𝐹𝑦 ) ) )
10 7 9 jca ( 𝜑 → ( 𝐹 ∈ ( 𝑅 GrpHom 𝑆 ) ∧ ∀ 𝑥𝐵𝑦𝐵 ( 𝐹 ‘ ( 𝑥 · 𝑦 ) ) = ( ( 𝐹𝑥 ) × ( 𝐹𝑦 ) ) ) )
11 1 2 3 isrnghm ( 𝐹 ∈ ( 𝑅 RngHomo 𝑆 ) ↔ ( ( 𝑅 ∈ Rng ∧ 𝑆 ∈ Rng ) ∧ ( 𝐹 ∈ ( 𝑅 GrpHom 𝑆 ) ∧ ∀ 𝑥𝐵𝑦𝐵 ( 𝐹 ‘ ( 𝑥 · 𝑦 ) ) = ( ( 𝐹𝑥 ) × ( 𝐹𝑦 ) ) ) ) )
12 8 10 11 sylanbrc ( 𝜑𝐹 ∈ ( 𝑅 RngHomo 𝑆 ) )