Metamath Proof Explorer


Theorem ixpeq1i

Description: Equality inference for infinite Cartesian product. (Contributed by GG, 1-Sep-2025)

Ref Expression
Hypothesis ixpeq1i.1 ⊢ 𝐴 = 𝐵
Assertion ixpeq1i X 𝑥 ∈ 𝐴 𝐶 = X 𝑥 ∈ 𝐵 𝐶

Proof

Step Hyp Ref Expression
1 ixpeq1i.1 ⊢ 𝐴 = 𝐵
2 1 eleq2i ⊢ ( 𝑥 ∈ 𝐴 ↔ 𝑥 ∈ 𝐵 )
3 2 abbii ⊢ { 𝑥 ∣ 𝑥 ∈ 𝐴 } = { 𝑥 ∣ 𝑥 ∈ 𝐵 }
4 3 fneq2i ⊢ ( 𝑓 Fn { 𝑥 ∣ 𝑥 ∈ 𝐴 } ↔ 𝑓 Fn { 𝑥 ∣ 𝑥 ∈ 𝐵 } )
5 2 imbi1i ⊢ ( ( 𝑥 ∈ 𝐴 → ( 𝑓 ‘ 𝑥 ) ∈ 𝐶 ) ↔ ( 𝑥 ∈ 𝐵 → ( 𝑓 ‘ 𝑥 ) ∈ 𝐶 ) )
6 5 ralbii2 ⊢ ( ∀ 𝑥 ∈ 𝐴 ( 𝑓 ‘ 𝑥 ) ∈ 𝐶 ↔ ∀ 𝑥 ∈ 𝐵 ( 𝑓 ‘ 𝑥 ) ∈ 𝐶 )
7 4 6 anbi12i ⊢ ( ( 𝑓 Fn { 𝑥 ∣ 𝑥 ∈ 𝐴 } ∧ ∀ 𝑥 ∈ 𝐴 ( 𝑓 ‘ 𝑥 ) ∈ 𝐶 ) ↔ ( 𝑓 Fn { 𝑥 ∣ 𝑥 ∈ 𝐵 } ∧ ∀ 𝑥 ∈ 𝐵 ( 𝑓 ‘ 𝑥 ) ∈ 𝐶 ) )
8 7 abbii ⊢ { 𝑓 ∣ ( 𝑓 Fn { 𝑥 ∣ 𝑥 ∈ 𝐴 } ∧ ∀ 𝑥 ∈ 𝐴 ( 𝑓 ‘ 𝑥 ) ∈ 𝐶 ) } = { 𝑓 ∣ ( 𝑓 Fn { 𝑥 ∣ 𝑥 ∈ 𝐵 } ∧ ∀ 𝑥 ∈ 𝐵 ( 𝑓 ‘ 𝑥 ) ∈ 𝐶 ) }
9 df-ixp ⊢ X 𝑥 ∈ 𝐴 𝐶 = { 𝑓 ∣ ( 𝑓 Fn { 𝑥 ∣ 𝑥 ∈ 𝐴 } ∧ ∀ 𝑥 ∈ 𝐴 ( 𝑓 ‘ 𝑥 ) ∈ 𝐶 ) }
10 df-ixp ⊢ X 𝑥 ∈ 𝐵 𝐶 = { 𝑓 ∣ ( 𝑓 Fn { 𝑥 ∣ 𝑥 ∈ 𝐵 } ∧ ∀ 𝑥 ∈ 𝐵 ( 𝑓 ‘ 𝑥 ) ∈ 𝐶 ) }
11 8 9 10 3eqtr4i ⊢ X 𝑥 ∈ 𝐴 𝐶 = X 𝑥 ∈ 𝐵 𝐶