Metamath Proof Explorer


Theorem kqffn

Description: The topological indistinguishability map is a function on the base. (Contributed by Mario Carneiro, 25-Aug-2015)

Ref Expression
Hypothesis kqval.2 ⊢ 𝐹 = ( 𝑥 ∈ 𝑋 ↦ { 𝑦 ∈ 𝐽 ∣ 𝑥 ∈ 𝑦 } )
Assertion kqffn ( 𝐽 ∈ 𝑉 → 𝐹 Fn 𝑋 )

Proof

Step Hyp Ref Expression
1 kqval.2 ⊢ 𝐹 = ( 𝑥 ∈ 𝑋 ↦ { 𝑦 ∈ 𝐽 ∣ 𝑥 ∈ 𝑦 } )
2 ssrab2 ⊢ { 𝑦 ∈ 𝐽 ∣ 𝑥 ∈ 𝑦 } ⊆ 𝐽
3 elpw2g ⊢ ( 𝐽 ∈ 𝑉 → ( { 𝑦 ∈ 𝐽 ∣ 𝑥 ∈ 𝑦 } ∈ 𝒫 𝐽 ↔ { 𝑦 ∈ 𝐽 ∣ 𝑥 ∈ 𝑦 } ⊆ 𝐽 ) )
4 2 3 mpbiri ⊢ ( 𝐽 ∈ 𝑉 → { 𝑦 ∈ 𝐽 ∣ 𝑥 ∈ 𝑦 } ∈ 𝒫 𝐽 )
5 4 adantr ⊢ ( ( 𝐽 ∈ 𝑉 ∧ 𝑥 ∈ 𝑋 ) → { 𝑦 ∈ 𝐽 ∣ 𝑥 ∈ 𝑦 } ∈ 𝒫 𝐽 )
6 5 1 fmptd ⊢ ( 𝐽 ∈ 𝑉 → 𝐹 : 𝑋 ⟶ 𝒫 𝐽 )
7 6 ffnd ⊢ ( 𝐽 ∈ 𝑉 → 𝐹 Fn 𝑋 )