Metamath Proof Explorer


Theorem lcfl1

Description: Property of a functional with a closed kernel. (Contributed by NM, 31-Dec-2014)

Ref Expression
Hypotheses lcfl1.c ⊢ 𝐶 = { 𝑓 ∈ 𝐹 ∣ ( ⊥ ‘ ( ⊥ ‘ ( 𝐿 ‘ 𝑓 ) ) ) = ( 𝐿 ‘ 𝑓 ) }
lcfl1.g ⊢ ( 𝜑 → 𝐺 ∈ 𝐹 )
Assertion lcfl1 ( 𝜑 → ( 𝐺 ∈ 𝐶 ↔ ( ⊥ ‘ ( ⊥ ‘ ( 𝐿 ‘ 𝐺 ) ) ) = ( 𝐿 ‘ 𝐺 ) ) )

Proof

Step Hyp Ref Expression
1 lcfl1.c ⊢ 𝐶 = { 𝑓 ∈ 𝐹 ∣ ( ⊥ ‘ ( ⊥ ‘ ( 𝐿 ‘ 𝑓 ) ) ) = ( 𝐿 ‘ 𝑓 ) }
2 lcfl1.g ⊢ ( 𝜑 → 𝐺 ∈ 𝐹 )
3 1 lcfl1lem ⊢ ( 𝐺 ∈ 𝐶 ↔ ( 𝐺 ∈ 𝐹 ∧ ( ⊥ ‘ ( ⊥ ‘ ( 𝐿 ‘ 𝐺 ) ) ) = ( 𝐿 ‘ 𝐺 ) ) )
4 2 biantrurd ⊢ ( 𝜑 → ( ( ⊥ ‘ ( ⊥ ‘ ( 𝐿 ‘ 𝐺 ) ) ) = ( 𝐿 ‘ 𝐺 ) ↔ ( 𝐺 ∈ 𝐹 ∧ ( ⊥ ‘ ( ⊥ ‘ ( 𝐿 ‘ 𝐺 ) ) ) = ( 𝐿 ‘ 𝐺 ) ) ) )
5 3 4 bitr4id ⊢ ( 𝜑 → ( 𝐺 ∈ 𝐶 ↔ ( ⊥ ‘ ( ⊥ ‘ ( 𝐿 ‘ 𝐺 ) ) ) = ( 𝐿 ‘ 𝐺 ) ) )