Metamath Proof Explorer


Theorem lss0ss

Description: The zero subspace is included in every subspace. ( sh0le analog.) (Contributed by NM, 27-Mar-2014) (Revised by Mario Carneiro, 19-Jun-2014)

Ref Expression
Hypotheses lss0cl.z 0 = ( 0g𝑊 )
lss0cl.s 𝑆 = ( LSubSp ‘ 𝑊 )
Assertion lss0ss ( ( 𝑊 ∈ LMod ∧ 𝑋𝑆 ) → { 0 } ⊆ 𝑋 )

Proof

Step Hyp Ref Expression
1 lss0cl.z 0 = ( 0g𝑊 )
2 lss0cl.s 𝑆 = ( LSubSp ‘ 𝑊 )
3 1 2 lss0cl ( ( 𝑊 ∈ LMod ∧ 𝑋𝑆 ) → 0𝑋 )
4 3 snssd ( ( 𝑊 ∈ LMod ∧ 𝑋𝑆 ) → { 0 } ⊆ 𝑋 )