Metamath Proof Explorer


Theorem lss0ss

Description: The zero subspace is included in every subspace. ( sh0le analog.) (Contributed by NM, 27-Mar-2014) (Revised by Mario Carneiro, 19-Jun-2014)

Ref Expression
Hypotheses lss0cl.z
|- .0. = ( 0g ` W )
lss0cl.s
|- S = ( LSubSp ` W )
Assertion lss0ss
|- ( ( W e. LMod /\ X e. S ) -> { .0. } C_ X )

Proof

Step Hyp Ref Expression
1 lss0cl.z
 |-  .0. = ( 0g ` W )
2 lss0cl.s
 |-  S = ( LSubSp ` W )
3 1 2 lss0cl
 |-  ( ( W e. LMod /\ X e. S ) -> .0. e. X )
4 3 snssd
 |-  ( ( W e. LMod /\ X e. S ) -> { .0. } C_ X )