Metamath Proof Explorer
Description: A vector X which doesn't belong to a subspace U is nonzero.
(Contributed by NM, 14-May-2015) (Revised by AV, 19-Jul-2022)
|
|
Ref |
Expression |
|
Hypotheses |
lssvneln0.o |
⊢ 0 = ( 0g ‘ 𝑊 ) |
|
|
lssvneln0.s |
⊢ 𝑆 = ( LSubSp ‘ 𝑊 ) |
|
|
lssvneln0.w |
⊢ ( 𝜑 → 𝑊 ∈ LMod ) |
|
|
lssvneln0.u |
⊢ ( 𝜑 → 𝑈 ∈ 𝑆 ) |
|
|
lssvneln0.n |
⊢ ( 𝜑 → ¬ 𝑋 ∈ 𝑈 ) |
|
Assertion |
lssvneln0 |
⊢ ( 𝜑 → 𝑋 ≠ 0 ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
lssvneln0.o |
⊢ 0 = ( 0g ‘ 𝑊 ) |
2 |
|
lssvneln0.s |
⊢ 𝑆 = ( LSubSp ‘ 𝑊 ) |
3 |
|
lssvneln0.w |
⊢ ( 𝜑 → 𝑊 ∈ LMod ) |
4 |
|
lssvneln0.u |
⊢ ( 𝜑 → 𝑈 ∈ 𝑆 ) |
5 |
|
lssvneln0.n |
⊢ ( 𝜑 → ¬ 𝑋 ∈ 𝑈 ) |
6 |
1 2
|
lss0cl |
⊢ ( ( 𝑊 ∈ LMod ∧ 𝑈 ∈ 𝑆 ) → 0 ∈ 𝑈 ) |
7 |
3 4 6
|
syl2anc |
⊢ ( 𝜑 → 0 ∈ 𝑈 ) |
8 |
|
eleq1a |
⊢ ( 0 ∈ 𝑈 → ( 𝑋 = 0 → 𝑋 ∈ 𝑈 ) ) |
9 |
7 8
|
syl |
⊢ ( 𝜑 → ( 𝑋 = 0 → 𝑋 ∈ 𝑈 ) ) |
10 |
9
|
necon3bd |
⊢ ( 𝜑 → ( ¬ 𝑋 ∈ 𝑈 → 𝑋 ≠ 0 ) ) |
11 |
5 10
|
mpd |
⊢ ( 𝜑 → 𝑋 ≠ 0 ) |