Metamath Proof Explorer


Theorem mpompts

Description: Express a two-argument function as a one-argument function, or vice-versa. (Contributed by Mario Carneiro, 24-Sep-2015)

Ref Expression
Assertion mpompts ( 𝑥 ∈ 𝐴 , 𝑦 ∈ 𝐵 ↦ 𝐶 ) = ( 𝑧 ∈ ( 𝐴 × 𝐵 ) ↦ ⦋ ( 1st ‘ 𝑧 ) / 𝑥 ⦌ ⦋ ( 2nd ‘ 𝑧 ) / 𝑦 ⦌ 𝐶 )

Proof

Step Hyp Ref Expression
1 mpomptsx ⊢ ( 𝑥 ∈ 𝐴 , 𝑦 ∈ 𝐵 ↦ 𝐶 ) = ( 𝑧 ∈ ∪ 𝑥 ∈ 𝐴 ( { 𝑥 } × 𝐵 ) ↦ ⦋ ( 1st ‘ 𝑧 ) / 𝑥 ⦌ ⦋ ( 2nd ‘ 𝑧 ) / 𝑦 ⦌ 𝐶 )
2 iunxpconst ⊢ ∪ 𝑥 ∈ 𝐴 ( { 𝑥 } × 𝐵 ) = ( 𝐴 × 𝐵 )
3 2 mpteq1i ⊢ ( 𝑧 ∈ ∪ 𝑥 ∈ 𝐴 ( { 𝑥 } × 𝐵 ) ↦ ⦋ ( 1st ‘ 𝑧 ) / 𝑥 ⦌ ⦋ ( 2nd ‘ 𝑧 ) / 𝑦 ⦌ 𝐶 ) = ( 𝑧 ∈ ( 𝐴 × 𝐵 ) ↦ ⦋ ( 1st ‘ 𝑧 ) / 𝑥 ⦌ ⦋ ( 2nd ‘ 𝑧 ) / 𝑦 ⦌ 𝐶 )
4 1 3 eqtri ⊢ ( 𝑥 ∈ 𝐴 , 𝑦 ∈ 𝐵 ↦ 𝐶 ) = ( 𝑧 ∈ ( 𝐴 × 𝐵 ) ↦ ⦋ ( 1st ‘ 𝑧 ) / 𝑥 ⦌ ⦋ ( 2nd ‘ 𝑧 ) / 𝑦 ⦌ 𝐶 )