Metamath Proof Explorer


Theorem mulcompq

Description: Multiplication of positive fractions is commutative. (Contributed by NM, 31-Aug-1995) (Revised by Mario Carneiro, 28-Apr-2013) (New usage is discouraged.)

Ref Expression
Assertion mulcompq ( 𝐴 ·pQ 𝐵 ) = ( 𝐵 ·pQ 𝐴 )

Proof

Step Hyp Ref Expression
1 mulcompi ⊢ ( ( 1st ‘ 𝐴 ) ·N ( 1st ‘ 𝐵 ) ) = ( ( 1st ‘ 𝐵 ) ·N ( 1st ‘ 𝐴 ) )
2 mulcompi ⊢ ( ( 2nd ‘ 𝐴 ) ·N ( 2nd ‘ 𝐵 ) ) = ( ( 2nd ‘ 𝐵 ) ·N ( 2nd ‘ 𝐴 ) )
3 1 2 opeq12i ⊢ ⟨ ( ( 1st ‘ 𝐴 ) ·N ( 1st ‘ 𝐵 ) ) , ( ( 2nd ‘ 𝐴 ) ·N ( 2nd ‘ 𝐵 ) ) ⟩ = ⟨ ( ( 1st ‘ 𝐵 ) ·N ( 1st ‘ 𝐴 ) ) , ( ( 2nd ‘ 𝐵 ) ·N ( 2nd ‘ 𝐴 ) ) ⟩
4 mulpipq2 ⊢ ( ( 𝐴 ∈ ( N × N ) ∧ 𝐵 ∈ ( N × N ) ) → ( 𝐴 ·pQ 𝐵 ) = ⟨ ( ( 1st ‘ 𝐴 ) ·N ( 1st ‘ 𝐵 ) ) , ( ( 2nd ‘ 𝐴 ) ·N ( 2nd ‘ 𝐵 ) ) ⟩ )
5 mulpipq2 ⊢ ( ( 𝐵 ∈ ( N × N ) ∧ 𝐴 ∈ ( N × N ) ) → ( 𝐵 ·pQ 𝐴 ) = ⟨ ( ( 1st ‘ 𝐵 ) ·N ( 1st ‘ 𝐴 ) ) , ( ( 2nd ‘ 𝐵 ) ·N ( 2nd ‘ 𝐴 ) ) ⟩ )
6 5 ancoms ⊢ ( ( 𝐴 ∈ ( N × N ) ∧ 𝐵 ∈ ( N × N ) ) → ( 𝐵 ·pQ 𝐴 ) = ⟨ ( ( 1st ‘ 𝐵 ) ·N ( 1st ‘ 𝐴 ) ) , ( ( 2nd ‘ 𝐵 ) ·N ( 2nd ‘ 𝐴 ) ) ⟩ )
7 3 4 6 3eqtr4a ⊢ ( ( 𝐴 ∈ ( N × N ) ∧ 𝐵 ∈ ( N × N ) ) → ( 𝐴 ·pQ 𝐵 ) = ( 𝐵 ·pQ 𝐴 ) )
8 mulpqf ⊢ ·pQ : ( ( N × N ) × ( N × N ) ) ⟶ ( N × N )
9 8 fdmi ⊢ dom ·pQ = ( ( N × N ) × ( N × N ) )
10 9 ndmovcom ⊢ ( ¬ ( 𝐴 ∈ ( N × N ) ∧ 𝐵 ∈ ( N × N ) ) → ( 𝐴 ·pQ 𝐵 ) = ( 𝐵 ·pQ 𝐴 ) )
11 7 10 pm2.61i ⊢ ( 𝐴 ·pQ 𝐵 ) = ( 𝐵 ·pQ 𝐴 )