Metamath Proof Explorer


Theorem necon1abid

Description: Contrapositive deduction for inequality. (Contributed by NM, 21-Aug-2007) (Proof shortened by Wolf Lammen, 24-Nov-2019)

Ref Expression
Hypothesis necon1abid.1 ⊢ ( 𝜑 → ( ¬ 𝜓 ↔ 𝐴 = 𝐵 ) )
Assertion necon1abid ( 𝜑 → ( 𝐴 ≠ 𝐵 ↔ 𝜓 ) )

Proof

Step Hyp Ref Expression
1 necon1abid.1 ⊢ ( 𝜑 → ( ¬ 𝜓 ↔ 𝐴 = 𝐵 ) )
2 notnotb ⊢ ( 𝜓 ↔ ¬ ¬ 𝜓 )
3 1 necon3bbid ⊢ ( 𝜑 → ( ¬ ¬ 𝜓 ↔ 𝐴 ≠ 𝐵 ) )
4 2 3 bitr2id ⊢ ( 𝜑 → ( 𝐴 ≠ 𝐵 ↔ 𝜓 ) )