Metamath Proof Explorer
		
		
		Theorem nfi
		Description:  Deduce that x is not free in ph from the definition.
       (Contributed by Wolf Lammen, 15-Sep-2021)
		
			
				
					|  |  | Ref | Expression | 
					
						|  | Hypothesis | nfi.1 | ⊢ ( ∃ 𝑥 𝜑  →  ∀ 𝑥 𝜑 ) | 
				
					|  | Assertion | nfi | ⊢  Ⅎ 𝑥 𝜑 | 
			
		
		
			
				Proof
				
					
						| Step | Hyp | Ref | Expression | 
						
							| 1 |  | nfi.1 | ⊢ ( ∃ 𝑥 𝜑  →  ∀ 𝑥 𝜑 ) | 
						
							| 2 |  | df-nf | ⊢ ( Ⅎ 𝑥 𝜑  ↔  ( ∃ 𝑥 𝜑  →  ∀ 𝑥 𝜑 ) ) | 
						
							| 3 | 1 2 | mpbir | ⊢ Ⅎ 𝑥 𝜑 |