Metamath Proof Explorer


Theorem nla0003

Description: Extending a linear order to subsets, the empty set is greater than any subset. Note in Alling, p. 3. (Contributed by RP, 28-Nov-2023)

Ref Expression
Hypotheses nla0001.defslts ⊢ < = { ⟨ 𝑎 , 𝑏 ⟩ ∣ ( 𝑎 ⊆ 𝑆 ∧ 𝑏 ⊆ 𝑆 ∧ ∀ 𝑥 ∈ 𝑎 ∀ 𝑦 ∈ 𝑏 𝑥 𝑅 𝑦 ) }
nla0001.set ⊢ ( 𝜑 → 𝐴 ∈ V )
nla0002.sset ⊢ ( 𝜑 → 𝐴 ⊆ 𝑆 )
Assertion nla0003 ( 𝜑 → 𝐴 < ∅ )

Proof

Step Hyp Ref Expression
1 nla0001.defslts ⊢ < = { ⟨ 𝑎 , 𝑏 ⟩ ∣ ( 𝑎 ⊆ 𝑆 ∧ 𝑏 ⊆ 𝑆 ∧ ∀ 𝑥 ∈ 𝑎 ∀ 𝑦 ∈ 𝑏 𝑥 𝑅 𝑦 ) }
2 nla0001.set ⊢ ( 𝜑 → 𝐴 ∈ V )
3 nla0002.sset ⊢ ( 𝜑 → 𝐴 ⊆ 𝑆 )
4 0ex ⊢ ∅ ∈ V
5 4 a1i ⊢ ( 𝜑 → ∅ ∈ V )
6 0ss ⊢ ∅ ⊆ 𝑆
7 6 a1i ⊢ ( 𝜑 → ∅ ⊆ 𝑆 )
8 ral0 ⊢ ∀ 𝑦 ∈ ∅ ∀ 𝑥 ∈ 𝐴 𝑥 𝑅 𝑦
9 ralcom ⊢ ( ∀ 𝑦 ∈ ∅ ∀ 𝑥 ∈ 𝐴 𝑥 𝑅 𝑦 ↔ ∀ 𝑥 ∈ 𝐴 ∀ 𝑦 ∈ ∅ 𝑥 𝑅 𝑦 )
10 8 9 mpbi ⊢ ∀ 𝑥 ∈ 𝐴 ∀ 𝑦 ∈ ∅ 𝑥 𝑅 𝑦
11 10 a1i ⊢ ( 𝜑 → ∀ 𝑥 ∈ 𝐴 ∀ 𝑦 ∈ ∅ 𝑥 𝑅 𝑦 )
12 3 7 11 3jca ⊢ ( 𝜑 → ( 𝐴 ⊆ 𝑆 ∧ ∅ ⊆ 𝑆 ∧ ∀ 𝑥 ∈ 𝐴 ∀ 𝑦 ∈ ∅ 𝑥 𝑅 𝑦 ) )
13 1 rp-brsslt ⊢ ( 𝐴 < ∅ ↔ ( ( 𝐴 ∈ V ∧ ∅ ∈ V ) ∧ ( 𝐴 ⊆ 𝑆 ∧ ∅ ⊆ 𝑆 ∧ ∀ 𝑥 ∈ 𝐴 ∀ 𝑦 ∈ ∅ 𝑥 𝑅 𝑦 ) ) )
14 2 5 12 13 syl21anbrc ⊢ ( 𝜑 → 𝐴 < ∅ )