Metamath Proof Explorer


Theorem nsspssun

Description: Negation of subclass expressed in terms of proper subclass and union. (Contributed by NM, 15-Sep-2004)

Ref Expression
Assertion nsspssun ( ¬ 𝐴 ⊆ 𝐵 ↔ 𝐵 ⊊ ( 𝐴 ∪ 𝐵 ) )

Proof

Step Hyp Ref Expression
1 ssun2 ⊢ 𝐵 ⊆ ( 𝐴 ∪ 𝐵 )
2 1 biantrur ⊢ ( ¬ ( 𝐴 ∪ 𝐵 ) ⊆ 𝐵 ↔ ( 𝐵 ⊆ ( 𝐴 ∪ 𝐵 ) ∧ ¬ ( 𝐴 ∪ 𝐵 ) ⊆ 𝐵 ) )
3 ssid ⊢ 𝐵 ⊆ 𝐵
4 3 biantru ⊢ ( 𝐴 ⊆ 𝐵 ↔ ( 𝐴 ⊆ 𝐵 ∧ 𝐵 ⊆ 𝐵 ) )
5 unss ⊢ ( ( 𝐴 ⊆ 𝐵 ∧ 𝐵 ⊆ 𝐵 ) ↔ ( 𝐴 ∪ 𝐵 ) ⊆ 𝐵 )
6 4 5 bitri ⊢ ( 𝐴 ⊆ 𝐵 ↔ ( 𝐴 ∪ 𝐵 ) ⊆ 𝐵 )
7 2 6 xchnxbir ⊢ ( ¬ 𝐴 ⊆ 𝐵 ↔ ( 𝐵 ⊆ ( 𝐴 ∪ 𝐵 ) ∧ ¬ ( 𝐴 ∪ 𝐵 ) ⊆ 𝐵 ) )
8 dfpss3 ⊢ ( 𝐵 ⊊ ( 𝐴 ∪ 𝐵 ) ↔ ( 𝐵 ⊆ ( 𝐴 ∪ 𝐵 ) ∧ ¬ ( 𝐴 ∪ 𝐵 ) ⊆ 𝐵 ) )
9 7 8 bitr4i ⊢ ( ¬ 𝐴 ⊆ 𝐵 ↔ 𝐵 ⊊ ( 𝐴 ∪ 𝐵 ) )