Metamath Proof Explorer


Theorem om2noseqfo

Description: Function statement for G . (Contributed by Scott Fenton, 18-Apr-2025)

Ref Expression
Hypotheses om2noseq.1 ⊢ ( 𝜑 → 𝐶 ∈ No )
om2noseq.2 ⊢ ( 𝜑 → 𝐺 = ( rec ( ( 𝑥 ∈ V ↦ ( 𝑥 +s 1s ) ) , 𝐶 ) ↾ ω ) )
om2noseq.3 ⊢ ( 𝜑 → 𝑍 = ( rec ( ( 𝑥 ∈ V ↦ ( 𝑥 +s 1s ) ) , 𝐶 ) “ ω ) )
Assertion om2noseqfo ( 𝜑 → 𝐺 : ω –onto→ 𝑍 )

Proof

Step Hyp Ref Expression
1 om2noseq.1 ⊢ ( 𝜑 → 𝐶 ∈ No )
2 om2noseq.2 ⊢ ( 𝜑 → 𝐺 = ( rec ( ( 𝑥 ∈ V ↦ ( 𝑥 +s 1s ) ) , 𝐶 ) ↾ ω ) )
3 om2noseq.3 ⊢ ( 𝜑 → 𝑍 = ( rec ( ( 𝑥 ∈ V ↦ ( 𝑥 +s 1s ) ) , 𝐶 ) “ ω ) )
4 frfnom ⊢ ( rec ( ( 𝑥 ∈ V ↦ ( 𝑥 +s 1s ) ) , 𝐶 ) ↾ ω ) Fn ω
5 2 fneq1d ⊢ ( 𝜑 → ( 𝐺 Fn ω ↔ ( rec ( ( 𝑥 ∈ V ↦ ( 𝑥 +s 1s ) ) , 𝐶 ) ↾ ω ) Fn ω ) )
6 4 5 mpbiri ⊢ ( 𝜑 → 𝐺 Fn ω )
7 df-ima ⊢ ( rec ( ( 𝑥 ∈ V ↦ ( 𝑥 +s 1s ) ) , 𝐶 ) “ ω ) = ran ( rec ( ( 𝑥 ∈ V ↦ ( 𝑥 +s 1s ) ) , 𝐶 ) ↾ ω )
8 7 eqcomi ⊢ ran ( rec ( ( 𝑥 ∈ V ↦ ( 𝑥 +s 1s ) ) , 𝐶 ) ↾ ω ) = ( rec ( ( 𝑥 ∈ V ↦ ( 𝑥 +s 1s ) ) , 𝐶 ) “ ω )
9 2 rneqd ⊢ ( 𝜑 → ran 𝐺 = ran ( rec ( ( 𝑥 ∈ V ↦ ( 𝑥 +s 1s ) ) , 𝐶 ) ↾ ω ) )
10 8 9 3 3eqtr4a ⊢ ( 𝜑 → ran 𝐺 = 𝑍 )
11 df-fo ⊢ ( 𝐺 : ω –onto→ 𝑍 ↔ ( 𝐺 Fn ω ∧ ran 𝐺 = 𝑍 ) )
12 6 10 11 sylanbrc ⊢ ( 𝜑 → 𝐺 : ω –onto→ 𝑍 )