Metamath Proof Explorer


Theorem onsupneqmaxlim0

Description: If the supremum of a class of ordinals is not in that class, then the supremum is a limit ordinal or empty. (Contributed by RP, 27-Jan-2025)

Ref Expression
Assertion onsupneqmaxlim0 ( 𝐴 ⊆ On → ( 𝐴 ⊆ ∪ 𝐴 → ∪ 𝐴 = ∪ ∪ 𝐴 ) )

Proof

Step Hyp Ref Expression
1 uniss ⊢ ( 𝐴 ⊆ ∪ 𝐴 → ∪ 𝐴 ⊆ ∪ ∪ 𝐴 )
2 ssorduni ⊢ ( 𝐴 ⊆ On → Ord ∪ 𝐴 )
3 orduniss ⊢ ( Ord ∪ 𝐴 → ∪ ∪ 𝐴 ⊆ ∪ 𝐴 )
4 2 3 syl ⊢ ( 𝐴 ⊆ On → ∪ ∪ 𝐴 ⊆ ∪ 𝐴 )
5 4 biantrud ⊢ ( 𝐴 ⊆ On → ( ∪ 𝐴 ⊆ ∪ ∪ 𝐴 ↔ ( ∪ 𝐴 ⊆ ∪ ∪ 𝐴 ∧ ∪ ∪ 𝐴 ⊆ ∪ 𝐴 ) ) )
6 eqss ⊢ ( ∪ 𝐴 = ∪ ∪ 𝐴 ↔ ( ∪ 𝐴 ⊆ ∪ ∪ 𝐴 ∧ ∪ ∪ 𝐴 ⊆ ∪ 𝐴 ) )
7 5 6 bitr4di ⊢ ( 𝐴 ⊆ On → ( ∪ 𝐴 ⊆ ∪ ∪ 𝐴 ↔ ∪ 𝐴 = ∪ ∪ 𝐴 ) )
8 1 7 imbitrid ⊢ ( 𝐴 ⊆ On → ( 𝐴 ⊆ ∪ 𝐴 → ∪ 𝐴 = ∪ ∪ 𝐴 ) )