Metamath Proof Explorer


Theorem onsupsucismax

Description: If the union of a set of ordinals is a successor ordinal, then that union is the maximum element of the set. This is not a bijection because sets where the maximum element is zero or a limit ordinal exist. Lemma 2.11 of Schloeder p. 5. (Contributed by RP, 27-Jan-2025)

Ref Expression
Assertion onsupsucismax ( ( 𝐴 ⊆ On ∧ 𝐴𝑉 ) → ( ∃ 𝑏 ∈ On 𝐴 = suc 𝑏 𝐴𝐴 ) )

Proof

Step Hyp Ref Expression
1 onsupnmax ( 𝐴 ⊆ On → ( ¬ 𝐴𝐴 𝐴 = 𝐴 ) )
2 ssorduni ( 𝐴 ⊆ On → Ord 𝐴 )
3 orduninsuc ( Ord 𝐴 → ( 𝐴 = 𝐴 ↔ ¬ ∃ 𝑏 ∈ On 𝐴 = suc 𝑏 ) )
4 2 3 syl ( 𝐴 ⊆ On → ( 𝐴 = 𝐴 ↔ ¬ ∃ 𝑏 ∈ On 𝐴 = suc 𝑏 ) )
5 1 4 sylibd ( 𝐴 ⊆ On → ( ¬ 𝐴𝐴 → ¬ ∃ 𝑏 ∈ On 𝐴 = suc 𝑏 ) )
6 5 con4d ( 𝐴 ⊆ On → ( ∃ 𝑏 ∈ On 𝐴 = suc 𝑏 𝐴𝐴 ) )
7 6 adantr ( ( 𝐴 ⊆ On ∧ 𝐴𝑉 ) → ( ∃ 𝑏 ∈ On 𝐴 = suc 𝑏 𝐴𝐴 ) )