Metamath Proof Explorer


Theorem oppglt

Description: less-than relation of an opposite group. (Contributed by Thierry Arnoux, 13-Apr-2018)

Ref Expression
Hypotheses oppglt.1 𝑂 = ( oppg𝑅 )
oppglt.2 < = ( lt ‘ 𝑅 )
Assertion oppglt ( 𝑅𝑉< = ( lt ‘ 𝑂 ) )

Proof

Step Hyp Ref Expression
1 oppglt.1 𝑂 = ( oppg𝑅 )
2 oppglt.2 < = ( lt ‘ 𝑅 )
3 eqid ( le ‘ 𝑅 ) = ( le ‘ 𝑅 )
4 3 2 pltfval ( 𝑅𝑉< = ( ( le ‘ 𝑅 ) ∖ I ) )
5 1 fvexi 𝑂 ∈ V
6 1 3 oppgle ( le ‘ 𝑅 ) = ( le ‘ 𝑂 )
7 eqid ( lt ‘ 𝑂 ) = ( lt ‘ 𝑂 )
8 6 7 pltfval ( 𝑂 ∈ V → ( lt ‘ 𝑂 ) = ( ( le ‘ 𝑅 ) ∖ I ) )
9 5 8 ax-mp ( lt ‘ 𝑂 ) = ( ( le ‘ 𝑅 ) ∖ I )
10 4 9 eqtr4di ( 𝑅𝑉< = ( lt ‘ 𝑂 ) )