Metamath Proof Explorer


Theorem opprnzr

Description: The opposite of a nonzero ring is nonzero. (Contributed by Mario Carneiro, 17-Jun-2015)

Ref Expression
Hypothesis opprnzr.1 𝑂 = ( oppr𝑅 )
Assertion opprnzr ( 𝑅 ∈ NzRing → 𝑂 ∈ NzRing )

Proof

Step Hyp Ref Expression
1 opprnzr.1 𝑂 = ( oppr𝑅 )
2 nzrring ( 𝑅 ∈ NzRing → 𝑅 ∈ Ring )
3 1 opprring ( 𝑅 ∈ Ring → 𝑂 ∈ Ring )
4 2 3 syl ( 𝑅 ∈ NzRing → 𝑂 ∈ Ring )
5 eqid ( Base ‘ 𝑅 ) = ( Base ‘ 𝑅 )
6 5 isnzr2 ( 𝑅 ∈ NzRing ↔ ( 𝑅 ∈ Ring ∧ 2o ≼ ( Base ‘ 𝑅 ) ) )
7 6 simprbi ( 𝑅 ∈ NzRing → 2o ≼ ( Base ‘ 𝑅 ) )
8 1 5 opprbas ( Base ‘ 𝑅 ) = ( Base ‘ 𝑂 )
9 8 isnzr2 ( 𝑂 ∈ NzRing ↔ ( 𝑂 ∈ Ring ∧ 2o ≼ ( Base ‘ 𝑅 ) ) )
10 4 7 9 sylanbrc ( 𝑅 ∈ NzRing → 𝑂 ∈ NzRing )