Metamath Proof Explorer


Theorem plngrnssp

Description: Planes are sets of points. (Contributed by Thierry Arnoux, 17-Jun-2026)

Ref Expression
Hypotheses plngval.p 𝑃 = ( Base ‘ 𝐺 )
plngval.i 𝐼 = ( Itv ‘ 𝐺 )
plngval.1 𝐿 = ( LineG ‘ 𝐺 )
plngval.e 𝐸 = ( hlG ‘ 𝐺 )
plngval.g ( 𝜑𝐺 ∈ TarskiG )
plngrnssp.h ( 𝜑𝐻 ∈ ran 𝐸 )
plngrnssp.x ( 𝜑𝑋𝐻 )
Assertion plngrnssp ( 𝜑𝑋𝑃 )

Proof

Step Hyp Ref Expression
1 plngval.p 𝑃 = ( Base ‘ 𝐺 )
2 plngval.i 𝐼 = ( Itv ‘ 𝐺 )
3 plngval.1 𝐿 = ( LineG ‘ 𝐺 )
4 plngval.e 𝐸 = ( hlG ‘ 𝐺 )
5 plngval.g ( 𝜑𝐺 ∈ TarskiG )
6 plngrnssp.h ( 𝜑𝐻 ∈ ran 𝐸 )
7 plngrnssp.x ( 𝜑𝑋𝐻 )
8 ssrab2 { 𝑥𝑃 ∣ ( 𝑥𝑎𝑥 ( ( hpG ‘ 𝐺 ) ‘ 𝑎 ) 𝑟 ∨ ∃ 𝑡𝑎 𝑡 ∈ ( 𝑥 𝐼 𝑟 ) ) } ⊆ 𝑃
9 7 ad3antrrr ( ( ( ( 𝜑𝑎 ∈ ran 𝐿 ) ∧ 𝑟 ∈ ( 𝑃𝑎 ) ) ∧ 𝐻 = ( 𝑎 𝐸 𝑟 ) ) → 𝑋𝐻 )
10 simpr ( ( ( ( 𝜑𝑎 ∈ ran 𝐿 ) ∧ 𝑟 ∈ ( 𝑃𝑎 ) ) ∧ 𝐻 = ( 𝑎 𝐸 𝑟 ) ) → 𝐻 = ( 𝑎 𝐸 𝑟 ) )
11 9 10 eleqtrd ( ( ( ( 𝜑𝑎 ∈ ran 𝐿 ) ∧ 𝑟 ∈ ( 𝑃𝑎 ) ) ∧ 𝐻 = ( 𝑎 𝐸 𝑟 ) ) → 𝑋 ∈ ( 𝑎 𝐸 𝑟 ) )
12 5 ad3antrrr ( ( ( ( 𝜑𝑎 ∈ ran 𝐿 ) ∧ 𝑟 ∈ ( 𝑃𝑎 ) ) ∧ 𝐻 = ( 𝑎 𝐸 𝑟 ) ) → 𝐺 ∈ TarskiG )
13 simpllr ( ( ( ( 𝜑𝑎 ∈ ran 𝐿 ) ∧ 𝑟 ∈ ( 𝑃𝑎 ) ) ∧ 𝐻 = ( 𝑎 𝐸 𝑟 ) ) → 𝑎 ∈ ran 𝐿 )
14 simplr ( ( ( ( 𝜑𝑎 ∈ ran 𝐿 ) ∧ 𝑟 ∈ ( 𝑃𝑎 ) ) ∧ 𝐻 = ( 𝑎 𝐸 𝑟 ) ) → 𝑟 ∈ ( 𝑃𝑎 ) )
15 1 2 3 4 12 13 14 plngval ( ( ( ( 𝜑𝑎 ∈ ran 𝐿 ) ∧ 𝑟 ∈ ( 𝑃𝑎 ) ) ∧ 𝐻 = ( 𝑎 𝐸 𝑟 ) ) → ( 𝑎 𝐸 𝑟 ) = { 𝑥𝑃 ∣ ( 𝑥𝑎𝑥 ( ( hpG ‘ 𝐺 ) ‘ 𝑎 ) 𝑟 ∨ ∃ 𝑡𝑎 𝑡 ∈ ( 𝑥 𝐼 𝑟 ) ) } )
16 11 15 eleqtrd ( ( ( ( 𝜑𝑎 ∈ ran 𝐿 ) ∧ 𝑟 ∈ ( 𝑃𝑎 ) ) ∧ 𝐻 = ( 𝑎 𝐸 𝑟 ) ) → 𝑋 ∈ { 𝑥𝑃 ∣ ( 𝑥𝑎𝑥 ( ( hpG ‘ 𝐺 ) ‘ 𝑎 ) 𝑟 ∨ ∃ 𝑡𝑎 𝑡 ∈ ( 𝑥 𝐼 𝑟 ) ) } )
17 8 16 sselid ( ( ( ( 𝜑𝑎 ∈ ran 𝐿 ) ∧ 𝑟 ∈ ( 𝑃𝑎 ) ) ∧ 𝐻 = ( 𝑎 𝐸 𝑟 ) ) → 𝑋𝑃 )
18 1 2 3 4 5 6 isplng ( 𝜑 → ∃ 𝑎 ∈ ran 𝐿𝑟 ∈ ( 𝑃𝑎 ) 𝐻 = ( 𝑎 𝐸 𝑟 ) )
19 17 18 r19.29vva ( 𝜑𝑋𝑃 )