Metamath Proof Explorer


Theorem pm2.65da

Description: Deduction for proof by contradiction. (Contributed by NM, 12-Jun-2014)

Ref Expression
Hypotheses pm2.65da.1 ( ( 𝜑𝜓 ) → 𝜒 )
pm2.65da.2 ( ( 𝜑𝜓 ) → ¬ 𝜒 )
Assertion pm2.65da ( 𝜑 → ¬ 𝜓 )

Proof

Step Hyp Ref Expression
1 pm2.65da.1 ( ( 𝜑𝜓 ) → 𝜒 )
2 pm2.65da.2 ( ( 𝜑𝜓 ) → ¬ 𝜒 )
3 1 ex ( 𝜑 → ( 𝜓𝜒 ) )
4 2 ex ( 𝜑 → ( 𝜓 → ¬ 𝜒 ) )
5 3 4 pm2.65d ( 𝜑 → ¬ 𝜓 )