Metamath Proof Explorer


Theorem rabsnt

Description: Truth implied by equality of a restricted class abstraction and a singleton. (Contributed by NM, 29-May-2006) (Proof shortened by Mario Carneiro, 23-Dec-2016)

Ref Expression
Hypotheses rabsnt.1 ⊢ 𝐵 ∈ V
rabsnt.2 ⊢ ( 𝑥 = 𝐵 → ( 𝜑 ↔ 𝜓 ) )
Assertion rabsnt ( { 𝑥 ∈ 𝐴 ∣ 𝜑 } = { 𝐵 } → 𝜓 )

Proof

Step Hyp Ref Expression
1 rabsnt.1 ⊢ 𝐵 ∈ V
2 rabsnt.2 ⊢ ( 𝑥 = 𝐵 → ( 𝜑 ↔ 𝜓 ) )
3 1 snid ⊢ 𝐵 ∈ { 𝐵 }
4 id ⊢ ( { 𝑥 ∈ 𝐴 ∣ 𝜑 } = { 𝐵 } → { 𝑥 ∈ 𝐴 ∣ 𝜑 } = { 𝐵 } )
5 3 4 eleqtrrid ⊢ ( { 𝑥 ∈ 𝐴 ∣ 𝜑 } = { 𝐵 } → 𝐵 ∈ { 𝑥 ∈ 𝐴 ∣ 𝜑 } )
6 2 elrab ⊢ ( 𝐵 ∈ { 𝑥 ∈ 𝐴 ∣ 𝜑 } ↔ ( 𝐵 ∈ 𝐴 ∧ 𝜓 ) )
7 6 simprbi ⊢ ( 𝐵 ∈ { 𝑥 ∈ 𝐴 ∣ 𝜑 } → 𝜓 )
8 5 7 syl ⊢ ( { 𝑥 ∈ 𝐴 ∣ 𝜑 } = { 𝐵 } → 𝜓 )