Metamath Proof Explorer


Theorem rabssdv

Description: Subclass of a restricted class abstraction (deduction form). (Contributed by NM, 2-Feb-2015)

Ref Expression
Hypothesis rabssdv.1 ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ∧ 𝜓 ) → 𝑥 ∈ 𝐵 )
Assertion rabssdv ( 𝜑 → { 𝑥 ∈ 𝐴 ∣ 𝜓 } ⊆ 𝐵 )

Proof

Step Hyp Ref Expression
1 rabssdv.1 ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ∧ 𝜓 ) → 𝑥 ∈ 𝐵 )
2 1 3exp ⊢ ( 𝜑 → ( 𝑥 ∈ 𝐴 → ( 𝜓 → 𝑥 ∈ 𝐵 ) ) )
3 2 ralrimiv ⊢ ( 𝜑 → ∀ 𝑥 ∈ 𝐴 ( 𝜓 → 𝑥 ∈ 𝐵 ) )
4 rabss ⊢ ( { 𝑥 ∈ 𝐴 ∣ 𝜓 } ⊆ 𝐵 ↔ ∀ 𝑥 ∈ 𝐴 ( 𝜓 → 𝑥 ∈ 𝐵 ) )
5 3 4 sylibr ⊢ ( 𝜑 → { 𝑥 ∈ 𝐴 ∣ 𝜓 } ⊆ 𝐵 )