Metamath Proof Explorer


Theorem rspcsbela

Description: Special case related to rspsbc . (Contributed by NM, 10-Dec-2005) (Proof shortened by Eric Schmidt, 17-Jan-2007)

Ref Expression
Assertion rspcsbela ( ( 𝐴 ∈ 𝐵 ∧ ∀ 𝑥 ∈ 𝐵 𝐶 ∈ 𝐷 ) → ⦋ 𝐴 / 𝑥 ⦌ 𝐶 ∈ 𝐷 )

Proof

Step Hyp Ref Expression
1 rspsbc ⊢ ( 𝐴 ∈ 𝐵 → ( ∀ 𝑥 ∈ 𝐵 𝐶 ∈ 𝐷 → [ 𝐴 / 𝑥 ] 𝐶 ∈ 𝐷 ) )
2 sbcel1g ⊢ ( 𝐴 ∈ 𝐵 → ( [ 𝐴 / 𝑥 ] 𝐶 ∈ 𝐷 ↔ ⦋ 𝐴 / 𝑥 ⦌ 𝐶 ∈ 𝐷 ) )
3 1 2 sylibd ⊢ ( 𝐴 ∈ 𝐵 → ( ∀ 𝑥 ∈ 𝐵 𝐶 ∈ 𝐷 → ⦋ 𝐴 / 𝑥 ⦌ 𝐶 ∈ 𝐷 ) )
4 3 imp ⊢ ( ( 𝐴 ∈ 𝐵 ∧ ∀ 𝑥 ∈ 𝐵 𝐶 ∈ 𝐷 ) → ⦋ 𝐴 / 𝑥 ⦌ 𝐶 ∈ 𝐷 )