Metamath Proof Explorer


Theorem sbcied2

Description: Conversion of implicit substitution to explicit class substitution, deduction form. (Contributed by NM, 13-Dec-2014)

Ref Expression
Hypotheses sbcied2.1 ⊢ ( 𝜑 → 𝐴 ∈ 𝑉 )
sbcied2.2 ⊢ ( 𝜑 → 𝐴 = 𝐵 )
sbcied2.3 ⊢ ( ( 𝜑 ∧ 𝑥 = 𝐵 ) → ( 𝜓 ↔ 𝜒 ) )
Assertion sbcied2 ( 𝜑 → ( [ 𝐴 / 𝑥 ] 𝜓 ↔ 𝜒 ) )

Proof

Step Hyp Ref Expression
1 sbcied2.1 ⊢ ( 𝜑 → 𝐴 ∈ 𝑉 )
2 sbcied2.2 ⊢ ( 𝜑 → 𝐴 = 𝐵 )
3 sbcied2.3 ⊢ ( ( 𝜑 ∧ 𝑥 = 𝐵 ) → ( 𝜓 ↔ 𝜒 ) )
4 id ⊢ ( 𝑥 = 𝐴 → 𝑥 = 𝐴 )
5 4 2 sylan9eqr ⊢ ( ( 𝜑 ∧ 𝑥 = 𝐴 ) → 𝑥 = 𝐵 )
6 5 3 syldan ⊢ ( ( 𝜑 ∧ 𝑥 = 𝐴 ) → ( 𝜓 ↔ 𝜒 ) )
7 1 6 sbcied ⊢ ( 𝜑 → ( [ 𝐴 / 𝑥 ] 𝜓 ↔ 𝜒 ) )