Metamath Proof Explorer


Theorem sbi1lem

Description: Lemma for sbi1 . The core of the proof was extracted from a proof of SN. (Contributed by Wolf Lammen, 5-Jun-2026)

Ref Expression
Assertion sbi1lem ( ( [ 𝑡 / 𝑥 ] ( 𝜑𝜓 ) ∧ [ 𝑡 / 𝑥 ] 𝜑 ) → ∀ 𝑦 ( 𝑦 = 𝑡 → ∀ 𝑥 ( 𝑥 = 𝑦𝜓 ) ) )

Proof

Step Hyp Ref Expression
1 dfsbimp ( [ 𝑡 / 𝑥 ] ( 𝜑𝜓 ) → ∀ 𝑦 ( 𝑦 = 𝑡 → ∀ 𝑥 ( 𝑥 = 𝑦 → ( 𝜑𝜓 ) ) ) )
2 dfsbimp ( [ 𝑡 / 𝑥 ] 𝜑 → ∀ 𝑦 ( 𝑦 = 𝑡 → ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) ) )
3 ax-2 ( ( 𝑥 = 𝑦 → ( 𝜑𝜓 ) ) → ( ( 𝑥 = 𝑦𝜑 ) → ( 𝑥 = 𝑦𝜓 ) ) )
4 3 al2imi ( ∀ 𝑥 ( 𝑥 = 𝑦 → ( 𝜑𝜓 ) ) → ( ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) → ∀ 𝑥 ( 𝑥 = 𝑦𝜓 ) ) )
5 4 imim3i ( ( 𝑦 = 𝑡 → ∀ 𝑥 ( 𝑥 = 𝑦 → ( 𝜑𝜓 ) ) ) → ( ( 𝑦 = 𝑡 → ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) ) → ( 𝑦 = 𝑡 → ∀ 𝑥 ( 𝑥 = 𝑦𝜓 ) ) ) )
6 5 al2imi ( ∀ 𝑦 ( 𝑦 = 𝑡 → ∀ 𝑥 ( 𝑥 = 𝑦 → ( 𝜑𝜓 ) ) ) → ( ∀ 𝑦 ( 𝑦 = 𝑡 → ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) ) → ∀ 𝑦 ( 𝑦 = 𝑡 → ∀ 𝑥 ( 𝑥 = 𝑦𝜓 ) ) ) )
7 1 2 6 syl2im ( [ 𝑡 / 𝑥 ] ( 𝜑𝜓 ) → ( [ 𝑡 / 𝑥 ] 𝜑 → ∀ 𝑦 ( 𝑦 = 𝑡 → ∀ 𝑥 ( 𝑥 = 𝑦𝜓 ) ) ) )
8 7 imp ( ( [ 𝑡 / 𝑥 ] ( 𝜑𝜓 ) ∧ [ 𝑡 / 𝑥 ] 𝜑 ) → ∀ 𝑦 ( 𝑦 = 𝑡 → ∀ 𝑥 ( 𝑥 = 𝑦𝜓 ) ) )