Metamath Proof Explorer


Theorem sbimi

Description: Distribute substitution over implication. (Contributed by NM, 25-Jun-1998) Revise df-sb . (Revised by BJ, 22-Dec-2020) (Proof shortened by Steven Nguyen, 24-Jul-2023)

Ref Expression
Hypothesis sbimi.1 ⊢ ( 𝜑 → 𝜓 )
Assertion sbimi ( [ 𝑡 / 𝑥 ] 𝜑 → [ 𝑡 / 𝑥 ] 𝜓 )

Proof

Step Hyp Ref Expression
1 sbimi.1 ⊢ ( 𝜑 → 𝜓 )
2 1 sbt ⊢ [ 𝑡 / 𝑥 ] ( 𝜑 → 𝜓 )
3 sbi1 ⊢ ( [ 𝑡 / 𝑥 ] ( 𝜑 → 𝜓 ) → ( [ 𝑡 / 𝑥 ] 𝜑 → [ 𝑡 / 𝑥 ] 𝜓 ) )
4 2 3 ax-mp ⊢ ( [ 𝑡 / 𝑥 ] 𝜑 → [ 𝑡 / 𝑥 ] 𝜓 )