Metamath Proof Explorer


Theorem sbimi

Description: Distribute substitution over implication. (Contributed by NM, 25-Jun-1998) Revise df-sb . (Revised by BJ, 22-Dec-2020) (Proof shortened by Steven Nguyen, 24-Jul-2023)

Ref Expression
Hypothesis sbimi.1
|- ( ph -> ps )
Assertion sbimi
|- ( [ t / x ] ph -> [ t / x ] ps )

Proof

Step Hyp Ref Expression
1 sbimi.1
 |-  ( ph -> ps )
2 1 sbt
 |-  [ t / x ] ( ph -> ps )
3 sbi1
 |-  ( [ t / x ] ( ph -> ps ) -> ( [ t / x ] ph -> [ t / x ] ps ) )
4 2 3 ax-mp
 |-  ( [ t / x ] ph -> [ t / x ] ps )