Metamath Proof Explorer


Theorem smffmptf

Description: A function measurable w.r.t. to a sigma-algebra, is actually a function. (Contributed by Glauco Siliprandi, 5-Jan-2025)

Ref Expression
Hypotheses smffmptf.x ⊢ Ⅎ 𝑥 𝜑
smffmptf.a ⊢ Ⅎ 𝑥 𝐴
smffmptf.s ⊢ ( 𝜑 → 𝑆 ∈ SAlg )
smffmptf.b ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ) → 𝐵 ∈ 𝑉 )
smffmptf.m ⊢ ( 𝜑 → ( 𝑥 ∈ 𝐴 ↦ 𝐵 ) ∈ ( SMblFn ‘ 𝑆 ) )
Assertion smffmptf ( 𝜑 → ( 𝑥 ∈ 𝐴 ↦ 𝐵 ) : 𝐴 ⟶ ℝ )

Proof

Step Hyp Ref Expression
1 smffmptf.x ⊢ Ⅎ 𝑥 𝜑
2 smffmptf.a ⊢ Ⅎ 𝑥 𝐴
3 smffmptf.s ⊢ ( 𝜑 → 𝑆 ∈ SAlg )
4 smffmptf.b ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ) → 𝐵 ∈ 𝑉 )
5 smffmptf.m ⊢ ( 𝜑 → ( 𝑥 ∈ 𝐴 ↦ 𝐵 ) ∈ ( SMblFn ‘ 𝑆 ) )
6 eqid ⊢ dom ( 𝑥 ∈ 𝐴 ↦ 𝐵 ) = dom ( 𝑥 ∈ 𝐴 ↦ 𝐵 )
7 3 5 6 smff ⊢ ( 𝜑 → ( 𝑥 ∈ 𝐴 ↦ 𝐵 ) : dom ( 𝑥 ∈ 𝐴 ↦ 𝐵 ) ⟶ ℝ )
8 1 2 4 dmmpt1 ⊢ ( 𝜑 → dom ( 𝑥 ∈ 𝐴 ↦ 𝐵 ) = 𝐴 )
9 8 eqcomd ⊢ ( 𝜑 → 𝐴 = dom ( 𝑥 ∈ 𝐴 ↦ 𝐵 ) )
10 9 feq2d ⊢ ( 𝜑 → ( ( 𝑥 ∈ 𝐴 ↦ 𝐵 ) : 𝐴 ⟶ ℝ ↔ ( 𝑥 ∈ 𝐴 ↦ 𝐵 ) : dom ( 𝑥 ∈ 𝐴 ↦ 𝐵 ) ⟶ ℝ ) )
11 7 10 mpbird ⊢ ( 𝜑 → ( 𝑥 ∈ 𝐴 ↦ 𝐵 ) : 𝐴 ⟶ ℝ )