Metamath Proof Explorer


Theorem snjust

Description: Soundness justification theorem for df-sn . (Contributed by Rodolfo Medina, 28-Apr-2010) (Proof shortened by Andrew Salmon, 29-Jun-2011)

Ref Expression
Assertion snjust { 𝑥 ∣ 𝑥 = 𝐴 } = { 𝑦 ∣ 𝑦 = 𝐴 }

Proof

Step Hyp Ref Expression
1 eqeq1 ⊢ ( 𝑥 = 𝑧 → ( 𝑥 = 𝐴 ↔ 𝑧 = 𝐴 ) )
2 1 cbvabv ⊢ { 𝑥 ∣ 𝑥 = 𝐴 } = { 𝑧 ∣ 𝑧 = 𝐴 }
3 eqeq1 ⊢ ( 𝑧 = 𝑦 → ( 𝑧 = 𝐴 ↔ 𝑦 = 𝐴 ) )
4 3 cbvabv ⊢ { 𝑧 ∣ 𝑧 = 𝐴 } = { 𝑦 ∣ 𝑦 = 𝐴 }
5 2 4 eqtri ⊢ { 𝑥 ∣ 𝑥 = 𝐴 } = { 𝑦 ∣ 𝑦 = 𝐴 }