Metamath Proof Explorer


Theorem spsbbi

Description: Biconditional property for substitution. Closed form of sbbii . Specialization of biconditional. (Contributed by NM, 2-Jun-1993) Revise df-sb . (Revised by BJ, 22-Dec-2020)

Ref Expression
Assertion spsbbi ( ∀ 𝑥 ( 𝜑 ↔ 𝜓 ) → ( [ 𝑡 / 𝑥 ] 𝜑 ↔ [ 𝑡 / 𝑥 ] 𝜓 ) )

Proof

Step Hyp Ref Expression
1 biimp ⊢ ( ( 𝜑 ↔ 𝜓 ) → ( 𝜑 → 𝜓 ) )
2 1 alimi ⊢ ( ∀ 𝑥 ( 𝜑 ↔ 𝜓 ) → ∀ 𝑥 ( 𝜑 → 𝜓 ) )
3 spsbim ⊢ ( ∀ 𝑥 ( 𝜑 → 𝜓 ) → ( [ 𝑡 / 𝑥 ] 𝜑 → [ 𝑡 / 𝑥 ] 𝜓 ) )
4 2 3 syl ⊢ ( ∀ 𝑥 ( 𝜑 ↔ 𝜓 ) → ( [ 𝑡 / 𝑥 ] 𝜑 → [ 𝑡 / 𝑥 ] 𝜓 ) )
5 biimpr ⊢ ( ( 𝜑 ↔ 𝜓 ) → ( 𝜓 → 𝜑 ) )
6 5 alimi ⊢ ( ∀ 𝑥 ( 𝜑 ↔ 𝜓 ) → ∀ 𝑥 ( 𝜓 → 𝜑 ) )
7 spsbim ⊢ ( ∀ 𝑥 ( 𝜓 → 𝜑 ) → ( [ 𝑡 / 𝑥 ] 𝜓 → [ 𝑡 / 𝑥 ] 𝜑 ) )
8 6 7 syl ⊢ ( ∀ 𝑥 ( 𝜑 ↔ 𝜓 ) → ( [ 𝑡 / 𝑥 ] 𝜓 → [ 𝑡 / 𝑥 ] 𝜑 ) )
9 4 8 impbid ⊢ ( ∀ 𝑥 ( 𝜑 ↔ 𝜓 ) → ( [ 𝑡 / 𝑥 ] 𝜑 ↔ [ 𝑡 / 𝑥 ] 𝜓 ) )