Metamath Proof Explorer


Theorem sscls

Description: A subset of a topology's underlying set is included in its closure. (Contributed by NM, 22-Feb-2007)

Ref Expression
Hypothesis clscld.1 ⊢ 𝑋 = ∪ 𝐽
Assertion sscls ( ( 𝐽 ∈ Top ∧ 𝑆 ⊆ 𝑋 ) → 𝑆 ⊆ ( ( cls ‘ 𝐽 ) ‘ 𝑆 ) )

Proof

Step Hyp Ref Expression
1 clscld.1 ⊢ 𝑋 = ∪ 𝐽
2 ssintub ⊢ 𝑆 ⊆ ∩ { 𝑥 ∈ ( Clsd ‘ 𝐽 ) ∣ 𝑆 ⊆ 𝑥 }
3 1 clsval ⊢ ( ( 𝐽 ∈ Top ∧ 𝑆 ⊆ 𝑋 ) → ( ( cls ‘ 𝐽 ) ‘ 𝑆 ) = ∩ { 𝑥 ∈ ( Clsd ‘ 𝐽 ) ∣ 𝑆 ⊆ 𝑥 } )
4 2 3 sseqtrrid ⊢ ( ( 𝐽 ∈ Top ∧ 𝑆 ⊆ 𝑋 ) → 𝑆 ⊆ ( ( cls ‘ 𝐽 ) ‘ 𝑆 ) )