Metamath Proof Explorer


Theorem sseldd

Description: Membership inference from subclass relationship. (Contributed by NM, 14-Dec-2004)

Ref Expression
Hypotheses sseld.1 ⊢ ( 𝜑 → 𝐴 ⊆ 𝐵 )
sseldd.2 ⊢ ( 𝜑 → 𝐶 ∈ 𝐴 )
Assertion sseldd ( 𝜑 → 𝐶 ∈ 𝐵 )

Proof

Step Hyp Ref Expression
1 sseld.1 ⊢ ( 𝜑 → 𝐴 ⊆ 𝐵 )
2 sseldd.2 ⊢ ( 𝜑 → 𝐶 ∈ 𝐴 )
3 1 sseld ⊢ ( 𝜑 → ( 𝐶 ∈ 𝐴 → 𝐶 ∈ 𝐵 ) )
4 2 3 mpd ⊢ ( 𝜑 → 𝐶 ∈ 𝐵 )