Metamath Proof Explorer


Theorem ssinss1

Description: Intersection preserves subclass relationship. (Contributed by NM, 14-Sep-1999) (Proof shortened by Umit Teoman Dogan, 10-Jun-2026)

Ref Expression
Assertion ssinss1 ( 𝐴𝐶 → ( 𝐴𝐵 ) ⊆ 𝐶 )

Proof

Step Hyp Ref Expression
1 ssrin ( 𝐴𝐶 → ( 𝐴𝐵 ) ⊆ ( 𝐶𝐵 ) )
2 inss1 ( 𝐶𝐵 ) ⊆ 𝐶
3 1 2 sstrdi ( 𝐴𝐶 → ( 𝐴𝐵 ) ⊆ 𝐶 )