Metamath Proof Explorer


Theorem inss

Description: Inclusion of an intersection of two classes. (Contributed by NM, 30-Oct-2014)

Ref Expression
Assertion inss ( ( 𝐴 ⊆ 𝐶 ∨ 𝐵 ⊆ 𝐶 ) → ( 𝐴 ∩ 𝐵 ) ⊆ 𝐶 )

Proof

Step Hyp Ref Expression
1 ssinss1 ⊢ ( 𝐴 ⊆ 𝐶 → ( 𝐴 ∩ 𝐵 ) ⊆ 𝐶 )
2 incom ⊢ ( 𝐴 ∩ 𝐵 ) = ( 𝐵 ∩ 𝐴 )
3 ssinss1 ⊢ ( 𝐵 ⊆ 𝐶 → ( 𝐵 ∩ 𝐴 ) ⊆ 𝐶 )
4 2 3 eqsstrid ⊢ ( 𝐵 ⊆ 𝐶 → ( 𝐴 ∩ 𝐵 ) ⊆ 𝐶 )
5 1 4 jaoi ⊢ ( ( 𝐴 ⊆ 𝐶 ∨ 𝐵 ⊆ 𝐶 ) → ( 𝐴 ∩ 𝐵 ) ⊆ 𝐶 )