Metamath Proof Explorer


Theorem eqsstrid

Description: A chained subclass and equality deduction. (Contributed by NM, 25-Apr-2004)

Ref Expression
Hypotheses eqsstrid.1 ⊢ 𝐴 = 𝐵
eqsstrid.2 ⊢ ( 𝜑 → 𝐵 ⊆ 𝐶 )
Assertion eqsstrid ( 𝜑 → 𝐴 ⊆ 𝐶 )

Proof

Step Hyp Ref Expression
1 eqsstrid.1 ⊢ 𝐴 = 𝐵
2 eqsstrid.2 ⊢ ( 𝜑 → 𝐵 ⊆ 𝐶 )
3 1 sseq1i ⊢ ( 𝐴 ⊆ 𝐶 ↔ 𝐵 ⊆ 𝐶 )
4 2 3 sylibr ⊢ ( 𝜑 → 𝐴 ⊆ 𝐶 )